Electrical Engineering (EE)>Test: Stability Analysis Download as PDF
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10 Questions MCQ Test | Test: Stability Analysis
Test: Stability Analysis for Electrical Engineering (EE) 2023 is part of Electrical Engineering (EE) preparation. The Test: Stability Analysis questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Stability Analysis MCQs are made for Electrical Engineering (EE) 2023 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Stability Analysis below.
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Test: Stability Analysis - Question 1
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First column elements of the Routh’s tabulation are 3, 5, -3/4, ½, 2. It means that there are:
Detailed Solution for Test: Stability Analysis - Question 1
Explanation: Routh hurwitz criteria is used to find the stability of the system and this is determined by the number of roots in which the number of roots is equal to the number of sign changes.
Test: Stability Analysis - Question 2
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Assertion (A): Feedback control system offer more accurate control over open-loop systems.
Reason (R): The feedback path establishes a link for input and output comparison and subsequent error correction.
Reason (R): The feedback path establishes a link for input and output comparison and subsequent error correction.
Detailed Solution for Test: Stability Analysis - Question 2
Explanation: Feedback control system offers more accuracy and also reduces the gain of the system and establishes the link for input and output comparison and subsequent error correction.
Test: Stability Analysis - Question 3
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Consider the following statements:
Detailed Solution for Test: Stability Analysis - Question 3
Explanation: Feedback reduces error and can cause stable system to become unstable and also can make unstable system stable.
Test: Stability Analysis - Question 4
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The Routh-Hurwitz criterion cannot be applied when the characteristic equation of the system contains any coefficients which is :
Detailed Solution for Test: Stability Analysis - Question 4
Explanation: The Routh-Hurwitz criterion cannot be applied when the characteristic equation of the system contains any coefficients which is negative real, both exponential and sinusoidal function of s.
Test: Stability Analysis - Question 5
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The following characteristic equation results in stable operation of the feedback system s3+4s2+10s+11=0
Detailed Solution for Test: Stability Analysis - Question 5
Explanation: Stable operation can be checked using the Routh-Hurwitz criterion where the first row of the the table is checked and with that.
Test: Stability Analysis - Question 6
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Consider the following statements:
Routh-Hurwitz criterion gives:
1. Absolute stability
2. The number of roots lying on the right half of the s-plane
3. The gain margin and the phase margin
Detailed Solution for Test: Stability Analysis - Question 6
Explanation: Routh-Hurwitz criterion gives absolute stability and number of roots lying on the right half of the s-plane.
Test: Stability Analysis - Question 7
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The given characteristic equation s4+s3+2s2+2s+3=0 has:
Detailed Solution for Test: Stability Analysis - Question 7
Explanation: The stability analysis is done using Routh-Hurwitz criterion and hence the number of roots on the right is calculated.
Test: Stability Analysis - Question 8
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Which of the following techniques is utilized to determine at the actual point at which the root locus crosses the imaginary axis?
Detailed Solution for Test: Stability Analysis - Question 8
Explanation: Routh-Hurwitz technique is utilized to determine at the actual point at which the root locus crosses the imaginary axis.
Test: Stability Analysis - Question 9
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The characteristic equation of a control system is given by s6+2s5+8s4+12s3+20s2+16s+16=0 . The number of the roots of the equation which lie on the imaginary axis of s-plane:
Detailed Solution for Test: Stability Analysis - Question 9
Explanation: The stability analysis is done using Routh-Hurwitz criterion and hence the number of roots on the right is calculated.
Test: Stability Analysis - Question 10
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Assertion (A): A linear, negative feedback control system is invariable stable if its open loop configuration is stable
Reason (R): the negative feedback reduces the overall gain of the feedback.
Detailed Solution for Test: Stability Analysis - Question 10
Explanation: A linear, negative feedback control system is not necessarily stable if its open loop configuration is stable.
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